C++STL算法 mismatch 中string.c_str()无法直接放到容器中

vs下的输出结果如下

.天地玄黄 日月盈昃 辰宿列张 寒来暑往 秋收冬藏 闰余成岁 闰余成岁
8 0 8 8 8 8 8 8
天地玄黄 日月盈昃 辰宿列张 寒来暑往 秋收冬藏 闰余成岁 律吕调阳
8 0 8 8 8 8 8 8
闰余成岁 7
律吕调阳 7

#include<iostream>
#include<cstdlib>
#include<vector>
#include<deque>
#include<algorithm>

using namespace std;

template <typename Container>
void print(Container c) {for_each(c.begin(), c.end(), [](auto i) {cout << i << " "; });cout << endl;}
template <typename Container>
void printlen(Container c) {for_each(c.begin(), c.end(), [](auto i) {cout << strlen(i) << "\t"; });cout << endl;}

int main()
{
	vector<const char*> cvec;
	cvec.push_back("天地玄黄");
	cvec.push_back(string("宇宙洪荒").c_str());
	const char* v3 = "日月盈昃";
	cvec.push_back(v3);
	char v4[] = "辰宿列张";
	cvec.push_back(v4);
	const char* v5 = "寒来暑往";
	cvec.push_back(v5);
	cvec.push_back("秋收冬藏");
	cvec.push_back((const char*)"闰余成岁");
	cvec.push_back("闰余成岁");

	deque<char*> cdeq;
	cdeq.push_back(const_cast<char*>("天地玄黄"));
	cdeq.push_back(const_cast<char*>((string("宇宙洪荒")).c_str()));
	char c3[] = "日月盈昃";
	cdeq.push_back(c3);
	const char* c4 = "辰宿列张";
	cdeq.push_back(const_cast<char*>(c4));
	const char* c5 = "寒来暑往";
	cdeq.push_back(const_cast<char*>(c5));
	string s("秋收冬藏");
	char c[100];
	strncpy_s(c, s.size() + 1, s.c_str(), s.size() + 1);
	cdeq.push_back((char*)c);
	cdeq.push_back((char*)"闰余成岁");
	const size_t sz = 9;
	const char c6[sz] = "律吕调阳";
	char c7[sz] = "";
	strncpy_s(c7, sz, c6, strlen(c6) + 1);
	cdeq.push_back(c7);

	print<vector<const char*>>(cvec); 
	printlen<vector<const char*>>(cvec);
	print<deque<char*>>(cdeq); 
	printlen<deque<char*>>(cdeq);

	if (cvec.size() > cdeq.size())return EXIT_FAILURE;

	pair<vector<const char*>::iterator, deque<char*>::iterator> result;
	result = mismatch(cvec.begin(), cvec.end(), cdeq.begin(),
		[](const char* s1, char* s2)->bool {
			size_t sa = strlen(s1);
			size_t sb = strlen(s2);
			return sa == sb ? not strncmp(s1, s2, sa) : false;
		});

	if (result.first != cvec.end())
	{
		cout << *result.first << "\t" << distance(cvec.begin(), result.first) << endl;
		cout << *result.second << "\t" << distance(cdeq.begin(), result.second) << endl;
	}
	else
	{
		cout << "onajikamoshiremasenn" << endl;
	}

	return EXIT_SUCCESS;
}